Computing the height of a Tkinter.Label on given text.
This is a first solution of code that does this. It doesn’t yet take care of the fact a Label takes whitespace into account, but it does look like a good start. The real work is in lin.count (), the other code is just enough to exercise lin.count ().
import Tkinter as Tk
import tkFont
import random
import sys
def genstr (j):
rno = random.randint(4,50)
ret_val = str(j) + ":"
for i in range (0, rno):
ret_val += "hello" + str(i)
return ret_val
def gendata (lh):
ret_val = []
for i in range(0,lh):
ret_val.append (genstr (i))
return ret_val
data = gendata (100)
root = Tk.Tk()
font = tkFont.Font(family='times', size=13)
class lines:
def __init__ (self):
self.lastct = 1 # remember where the cutoff was last work from there
def count (self, text, cutoff = 400):
global font
no_lines = 1
start_idx = 0
idx = self.lastct
while True:
if idx > len (text):
idx = len (text)
# shrink from guessed value
while font.measure (text[start_idx:idx - 1]) > cutoff:
if idx <= start_idx:
print "error"
sys.exit ()
else:
idx -= 1
self.lastct = idx - start_idx # adjust since was too big
# increase from guessed value (note: if first shrunk then done)
while (idx < len (text)
and font.measure (text[start_idx:idx]) < cutoff):
idx += 1
self.lastct = idx - start_idx # adjust since was too small
# next line has been determined
print "*" + text[start_idx:idx-1] + "*"
if idx == len(text) and font.measure (text[start_idx:]) < cutoff:
return no_lines
elif idx == len(text):
return no_lines + 1
else:
no_lines += 1
start_idx = idx - 1
idx = start_idx + self.lastct
lin = lines()
for i in range(0,len(data)):
lin.count(data[i], 450)
for i in range(0,min(len(data),10)):
l = Tk.Label(root)
l.pack()
l['text'] = data[i]
print i
no = lin.count (data[i], 450)
print "computed lines", no
l['width'] = 50
l['justify'] = Tk.LEFT
l['anchor'] = 'w'
l['wraplength'] = 450
l['padx']=10
l['pady'] = 5
l['height'] = no
l['font'] = font
if i % 2 == 0:
l['background'] = 'grey80'
else:
l['background'] = 'grey70'
root.mainloop()
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